9
cb219
5y

just did a stochastic exam for my cs degree and let's say it didn't go very well (i'm not very good at stochastic)๐Ÿ˜’
had a question like: "how many possibilities exist if you divide 8 people into 2 equal groups of 4?" (with 5 different choices to answer)
shouldn't that be 8 over 4 (binomial)? so pick 4 people and 4 remain as the second group, that makes 70 combinations, as far as i know ...
but there wasn't any 70. I then divided by 2 so i got 35 which was one of the available answers๐Ÿคท, is that correct? did i understand smth wrong?

Comments
  • 4
    35 is correct. You have to pick a group of 4 from 8 which is 8!/(4! * (8-4)!) = 70, but it doesn't matter which is the group you picked and which is the one leftover, so you divide by another 2.
  • 2
    @joycestick at least i checked the right answer ๐Ÿ˜…๐Ÿ˜
Add Comment