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asgs474970dThe lines 4 and 5 in that method adjust the appropriate indices and run recursively. "mid + 1" is the clue here
@asgs so that would mean the end parameter is inclusive. Otherwise it would be skipping mid?
Now I see the for (int i=0; i< (mid-low+1);i++)
What's looking for a <= so basically this would mean the Left side will always have the 1 more item than the right if and odd succeed array is the input?
Guess is the "indexes start at 0" thing that makes it tricky...
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