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Root826025y
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Just copy the value
Do
Decrease by one
Divide to original
if original mod copy =0 => return true
While (copy >2) -
I think the key hint for the third task is the data structure "dictionary" - somewhat unsurprisingly.
@melezorus34 Sounds like you need O(N) steps for that. If you try the other way around, i.e. divide by 2 and then by every odd number until SQRT(N), that would be much fewer steps. -
@melezorus34 That was my original approach but it still takes 2min per number...
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@Fast-Nop I know how to do it i just didnt want to. That would use too much time to process that. I know i just could use a smaller set but it dosent matter now im going to pass and that is enough. Also i have plans for revenge.
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@Gregozor2121 if you want, I can give you my compiled prank : mouse-ducker, with the source code cuz it ain't that complicated.
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Avyy7525yPrime checking is easy. Use miller rabin or bpsw.
Since your number is small(10 digits), probability of false positives will be nearly zero. Just keep in mind miller rabin will need strong witnesses -
@AvyChanna That was supposed to be a introductory class to java, i dont want to bring out the big guns here.
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@melezorus34 Sorry. I dont have any that i can post here. I will have to reject that offer. :(
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