2
WalkingBed
283d

Is there a way to simplify the following boolean expression..??

(x && !y) || (!x && y)

Comments
  • 14
  • 1
    And she is correct

    >>> def foo(x, y):
    >>> print((x and (not y)) or ((not x) and y))
    >>>
    >>> def bar(x, y):
    >>> print(x != y)
    >>>
    >>> def printer(func):
    >>> func(False,False)
    >>> func(False,True)
    >>> func(True,False)
    >>> func(True,True)

    >>> printer(foo)
    >>> print("--------")
    >>> printer(bar)

    False
    True
    True
    False
    --------
    False
    True
    True
    False
  • 2
    Yes, thanks @Voxera.

    I forgot to mention javascript tag, but I was able to find a simplified ternary operator version for this through her comment.

    (x ? !y : y)
  • 3
    @shehanthamel (!x ^ !y), or (!x != !y) (if x and y are already both booleans, you can just write x^y or x!=y)
  • 2
    DeMorgan Laws.

    Learn them.
  • 1
    @shehanthamel That works, but I'd probably use the first just for the sake of writing clear code.

    If they're bools, perhaps x !== y?
  • 1
    @shehanthamel
    If its Javascript then you can do one of:
    x ^ y - runs xor for x and y, works well in this case if x and y are bool only. Returns 1 or 0.
    !!x ^ !!y - converts to bool and runs xor. Returns 1 or 0.
    !!(!!x ^ !!y) - converts to bool, runs xor, converts result to bool true / false.

    So pick one for your use case :)
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