I need to build a dynamic regular expression with matching 0 or more char, but \w doesn’t work.
new RegExp(‘^\/\w*#’ + route, ‘i’)
Any solution? 🥺

I don't have the answer but my go to test website is regex101.com, put your expression there it will tell you what's wrong

@gitpush @heyheni the regular expression itself is correct. The problem is when dynamically build it from a string, \w and back slash don’t work.

@sunfishcc aaah not sure then, I rarely work with regex tbh :/

I'm not sure what you want to achieve...

new Regex('^\\\\....

If u need a \.

As the \ needs to be escaped two times!

@sunfishcc maybe try ACK the Perl regular expressions? It should offer you more control.

https://beyondgrep.com/why-ack/

there is also the possibility of using [:POSIX:] with regex.

https://regular-expressions.mobi/po...

@IntrusionCM match 0 to n char with \w, which doesn't work with new RegExp('...'). I get around with [a-z]. But this garbage blows my mind

@heyheni It's part of frontend redirect in React routing. Has to be JavaScript.

Meh. Tired braint fart.

Deleted my last comment as I totally misread the first line.

@IntrusionCM no problem. At least you try to help 👍 the inconsistency in JS made my pull my hair off

Digging in a mine field....

The only thing I remember was that new RegExp had a different behaviour in escaping and that the second argument is important - but I really have no clue if it applies in your situation.

And yes. Escaping in regex is most of the time madness - playing Hyde (brute forcing try and Error) and Jekyll (orgasmic happiness cause it makes all sense suddenly)

@sunfishcc
Try https://w3schools.com/jsref/...
From syntax part I see you are having trouble with escaping quote with "\\w"
Or simply /\w\

@sak96 wow! Make sense!