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Fast-Nop27945210dThough the mass of the car does not go into the equation. I could actually calculate the friction coefficient if you either gave how much time it took from 50 to 40, or what way you made during that time.
I learned from a coworker that some lady did a Dukes of Hazard style leap with her car about 45 minutes previous to my passing through that area. She spun around 180 and was going 70mph backwards. She hit a snow pile and launched air born. She landed on top of another snow pile. She was okay, but I bet she needed to change her shorts. She was going southbound and nearly went into the northbound lanes during this. She is very lucky how her flight ended.
Fast-Nop27945210d@Demolishun Let's say v is the speed, t is time, a acceleration, and g is the earth's gravity acceleration.
v1 = 50mph = 80km/h = 22.2m/s
v2 = 40mph = 64km/h = 17.8m/s
Since a = dv/dt, and assuming constant deceleration, we have:
a = (22.2m/s - 17.8m/s)/5s = 0.88 m/s^2.
Given that g = 9.81m/s^2, the friction coefficient is:
µ = a / g = 0.09.
That would be a typical range for ice on the road, i.e. "really fucking slick".
electrineer14159209dPardon my first attempt of this shitty meme.
Winter tires: exist