Such coincidence.

Could be the feed algorithm. I'm pretty sure I saw the second post in that picture before the first one... On my feed of course.

If someone asked me that in a interview I would leave. Definitely wouldn't want to work there if that's how they review your skills.

These rants were posted by the same guy.

@kerrermanisNL Why? I think it's a valid question to test junior devs' understanding of conditional statements.

@setyadi Plus it has been found to work. Even "senior" developers have given crazy answers to it.

@psudo This is mainly the thinking behind it.

It's not necessarily a hard task, but it certainly demonstrates the thought process of the person doing it.

Okay am i the only one who thinks thats wrong? Just use if()fizz and if()buzz and it will do exactly that, you dont need an if()fizzbuzz part.

@RazorSh4rk It's true, but that's showing you aren't at a beginner level anymore.

Also looking at it again, it has a small error as the loop should start at 1.

the FizzBuzz is only meant to separate those who can't code <i>at all</i>, from the rest.
by no means, it's there to evaluate your skills.
its like 2 levels below beginner, just good enough to dispel a good amount of "programmers"...

This is 3 lines of code but devRant is a small space so the formatting looks weird, but this is how i normally would do fizzbuzz

for (var i = 1; i < 101; i++) {
console.log( (i % 3 == 0 ? ( i % 5 == 0 ? "FizzBuzz" : "Fizz" ) : ( i % 5 == 0 ? "Buzz" : null ) ));
}

@alexdovzhanyn Maybe I'm just not familiar enough with js, but it looks like you're missing the printing out of numbers that aren't fizz or buzz.

@psudo oh shoot youre right! i print out null instead cause i didnt read the instructions 😂😂😂😂 if you replace the null with "i", itll work like expected

@alexdovzhanyn Need to get rid of those brackets too ;) one linerz fo dayz.