My own implementation for calculating if a number is even.
Full Code: https://ghostbin.com/paste/fkp6j

This kind of reminds me of my friend who wanted to add complexity to his code even though it was totally redundant to do so.

I assume this is a joke? I'm missing something. Is it supposed to be a comical example of overly verbose and complicated ways of achieving a trivial task. Also, and this may be deliberate, your array of evens is full of odds.

It's currently a meme. Especially in https://reddit.com/r/... there a many isEven functions which are more complicated as necessary

@Bimpfi OIC. That explains it. Thx.

Looks like some enterprise code to me :D

You are fooling us, right? 😅

@irene but you cant do log -1. but yeah it is wrong. he tests for !<= 0 and then adds 1. But this whole function is rubbish so...

bool isEven(n)
{
return n & 1 == 0;
}

@rkzo that's the right way! I've the same function. 😉

simplest:

if (int($x / 2) == ($x / 2)) {
#Number is even
}

Fuck divide and conquer.
Multiply and surrender is the only way!

@rkzo that's wrong right? It only works with unsigned?

I dont see the point why this doesnt work for signed?

@scholl3ss a negative number will result in n_digits = 1.

Why? 2 complement? I dont get it.

@scholl3ss log function always returns something positive

Oh, i was talking about num & 1 == 0

@scholl3ss oh, then yes, 2 bits complement. With 4 bits, 1111 == -8
And it fails.